SQR
Returns a square root of a number
Syntax:
Usage:
result = Sqr( number )
Parameters:
number
the number (greater than or equal to zero)
Return Value:
Returns the square root of the argument number.
If number equals zero, Sqr returns zero (0.0).
If number is less than zero, Sqr returns a special value representing "not defined", printing like "NaN" or "IND", exact text is platform dependent.
If number equals zero, Sqr returns zero (0.0).
If number is less than zero, Sqr returns a special value representing "not defined", printing like "NaN" or "IND", exact text is platform dependent.
Description:
This is the same as raising the argument number to the one-half power: y = x ^ (1/2) . The required number argument can be any valid numeric expression greater than or equal zero.
If a Longint or ULongint is passed to Sqr, it may be converted to Double precision first. For numbers over 2^52, this will cause a very small loss of precision. Without making any assumptions about the rounding method, the maximum error due to this will be Sqr(2^64) - Sqr(2^64-2^12), which is about 4.8e-7. However this may cause erroneous results if the floor or ceiling of this value is taken, and the result of this may be out by 1, particularly for square numbers and numbers that are close by.
Sqr can be overloaded as operator to accept user-defined types.
If a Longint or ULongint is passed to Sqr, it may be converted to Double precision first. For numbers over 2^52, this will cause a very small loss of precision. Without making any assumptions about the rounding method, the maximum error due to this will be Sqr(2^64) - Sqr(2^64-2^12), which is about 4.8e-7. However this may cause erroneous results if the floor or ceiling of this value is taken, and the result of this may be out by 1, particularly for square numbers and numbers that are close by.
Sqr can be overloaded as operator to accept user-defined types.
Examples:
'' Example of Sqr function: Pythagorean theorem
Dim As Single a, b
Print "Pythagorean theorem, right-angled triangle"
Print
Input "Please enter one leg side length: ", a
Input "Please enter the other leg side length: ", b
Print
Print "The hypotenuse has a length of: " & Sqr( a * a + b * b )
Dim As Single a, b
Print "Pythagorean theorem, right-angled triangle"
Input "Please enter one leg side length: ", a
Input "Please enter the other leg side length: ", b
Print "The hypotenuse has a length of: " & Sqr( a * a + b * b )
The output would look like:
Pythagorean theorem, right-angled triangle Please enter one leg side length: 1.5 Please enter the other leg side length: 2 The hypotenuse has a length of: 2.5
Differences from QB:
- None
See also:
Back to Math
