## Squares

General FreeBASIC programming questions.
BasicCoder2
Posts: 3635
Joined: Jan 01, 2009 7:03
Location: Australia

### Redundancy

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Last edited by BasicCoder2 on Feb 09, 2020 3:11, edited 1 time in total.
Richard
Posts: 3047
Joined: Jan 15, 2007 20:44
Location: Australia

### Re: Yah-Zip ( Test Bed )

albert wrote:( !!~~ COMPRESSION SUCCESS ~~!! )

Oh no, not again. How many times is that now ?
albert
Posts: 5927
Joined: Sep 28, 2006 2:41
Location: California, USA

### Re: Squares

@Richard

Sorry for the false wolf cry...

I tried 1 , 10 , 2 , 20 and it doesn't compress.

It was compressing a couple hundred bytes each loop , because of the 0 , 10 , 2 , 20 ( "2" - "0" happens every so often.. and confuses "20" )

Back to the drawing board!!!!
dodicat
Posts: 6767
Joined: Jan 10, 2006 20:30
Location: Scotland

### Re: Squares

I was having a cuppa today in a local garden centre when I noticed one of our Scottish Labour Party MSP'S doing likewise.
We don't often see Parliamentarians here, we are a bit remote.
I didn't trouble the fellow of course, but I emailed his office tonight regarding the threatened woodland.
Maybe he has a connection with these parts, and if so, and his alarm bells ring, I might not be completely alone.
(Maybe too many if's)
Good luck Albert . . . carry on.
albert
Posts: 5927
Joined: Sep 28, 2006 2:41
Location: California, USA

### Re: Squares

@Dodicat

Can this be resolved?? A new compression method..

===================================================
n1 = "00000000" + bin( *usp ) : usp+= 1
n1 = right( n1 , 8 )

v1 = val( "&B" + mid( n1 , 1 , 4 ) )
v2 = val( "&B" + mid( n1 , 5 , 4 ) )

if v1 < v2 then v3 = ( v2 - v1 )
if v1 > v2 then v3 = ( v1 - v2 )
if v1 = v2 then v3 = 0

bits1+= hex( v1 )
bits1+= hex( v3 )
==================================================
Got to resolve the v3 issue... v2 - v1 or v1 - v2 ??

Compresses 100,000 bytes in , to 1,200 bytes out , 98% : After 100 loops...

Here's the "Test-Bed" where i write the decompression..

Code: Select all

`Declare Function      compress_loop( chrs as string ) as stringDeclare Function decompress_loop( chrs as string ) as stringscreen 19'====================================================================='====================================================================='start program'====================================================================='=====================================================================dim as double time1 , time2 , time3 , time4do       randomize       dim as string s = ""    For n As Long = 1 To 8        s+=chr(Int(Rnd*256))    Next       time1=timer    'begin compress        dim as string comp = s            'do            '    dim as longint chk = len(comp) - 1            '    comp = compress_loop(comp)            '    if len(comp) >= chk then exit do            '    if inkey = chr( 27 ) then end            'loop            for a as longint = 1 to 1 step 1                comp = compress_loop(comp)            next    'end compress    time2 = timer       time3=timer    'begin decompress        dim as string final_out = comp        for a as longint = 1 to 1 step 1            final_out = decompress_loop(final_out)        next    'end decompress    time4 = timer      'sleep       print string(99,"=")    print "inp = " ; (s)    print string(99,"=")    print "out = " ; (final_out)    print    print "compress time   = "; time2-time1    print "decompress time = "; time4-time3    print       if s = final_out then print "Decompressed OK" else print "Decompression failed."    print string(99,"=")       sleep   loop until inkey = chr(27)sleepend'==============================================================================='==============================================================================='compress'==============================================================================='===============================================================================Function compress_loop( chrs as string ) as string       print "c inp = " ; len(chrs) ' , chrs        dim as string bits1 = ""    dim as string n1    dim as longint v1 , v2 , v3    dim as ubyte ptr usp = cptr( ubyte ptr , strptr( chrs ) )    for a as longint = 1 to len( chrs ) step 1                n1 = "00000000" + bin( *usp ) : usp+= 1        n1 = right( n1 , 8 )                v1 = val( "&B" + mid( n1 , 1 , 4 ) )        v2 = val( "&B" + mid( n1 , 5 , 4 ) )                if v1 < v2 then v3 = ( v2 - v1 )        if v1 > v2 then v3 = ( v1 - v2 )        if v1 = v2 then v3 = 0                bits1+= hex( v1 )        bits1+= hex( v3 )                'print n1 , v1 , v2 , v3        'sleep        'if inkey = " " then end            next        print "c out = " ; len( bits1 ) , bits1        dim as string final = ""    for a as longint = 1 to len( bits1 ) step 2        final+= chr( val( "&H" + mid( bits1 , a , 2 ) ) )    next        print "c fin = " ; len(final)       return final   end function'==============================================================================='============================================================================Function decompress_loop( chrs as string ) as string        print    print "d inp = " ; len( chrs )    dim as string bits = ""    for a as longint = 1 to len( chrs ) step 1        bits+= right( "00" + hex( chrs[ a - 1 ] ) , 2 )    next        print "d bit = " ; len( bits ) , bits        return chrs   end function`
albert
Posts: 5927
Joined: Sep 28, 2006 2:41
Location: California, USA

### Re: Squares

@Dodicat

I got it almost returning correct answers...

You got to adjust the val1 ( answer ) to equal "v2"

I was trying logic , to try to figure out when to add and when to subtract.. ( no luck!! )

Code: Select all

`Declare Function      compress_loop( chrs as string ) as stringDeclare Function decompress_loop( chrs as string ) as stringscreen 19'====================================================================='====================================================================='start program'====================================================================='=====================================================================dim as double time1 , time2 , time3 , time4do       randomize       dim as string s = ""    For n As Long = 1 To 8        s+=chr(Int(Rnd*256))    Next       time1=timer    'begin compress        dim as string comp = s            'do            '    dim as longint chk = len(comp) - 1            '    comp = compress_loop(comp)            '    if len(comp) >= chk then exit do            '    if inkey = chr( 27 ) then end            'loop            for a as longint = 1 to 1 step 1                comp = compress_loop(comp)            next    'end compress    time2 = timer       time3=timer    'begin decompress        dim as string final_out = comp        for a as longint = 1 to 1 step 1            final_out = decompress_loop(final_out)        next    'end decompress    time4 = timer      'sleep       print string(99,"=")    print "inp = " ; (s)    print string(99,"=")    print "out = " ; (final_out)    print    print "compress time   = "; time2-time1    print "decompress time = "; time4-time3    print       if s = final_out then print "Decompressed OK" else print "Decompression failed."    print string(99,"=")       sleep   loop until inkey = chr(27)sleepend'==============================================================================='==============================================================================='compress'==============================================================================='===============================================================================Function compress_loop( chrs as string ) as string       print "c inp = " ; len(chrs) ' , chrs        print "n1" , "v1" , "v2" , "v3" , "answer"        dim as string bits1 = ""    dim as string n1    dim as longint v1 , v2 , v3    dim as ubyte ptr usp = cptr( ubyte ptr , strptr( chrs ) )    for a as longint = 1 to len( chrs ) step 1                n1 = "00000000" + bin( *usp ) : usp+= 1        n1 = right( n1 , 8 )                v1 = val( "&B" + mid( n1 , 1 , 4 ) )        v2 = val( "&B" + mid( n1 , 5 , 4 ) )                if v1 < v2 then v3 = abs( v1 - v2 )        if v1 > v2 then v3 = ( v1 - v2 )        if v1 = v2 then v3 = 0                bits1+= hex( v1 )        bits1+= hex( v3 )                dim as longint val1        for b as longint = 1  to 15 step 1            if v1 < b and abs( v1 - b ) = v3 then val1 = b : exit for            if v1 > b and ( v1 - b ) = v3 then val1 = b : exit for        next        if v3 = 0 then val1 = v1                 print n1 , v1 , v2 , v3 , val1        sleep        if inkey = " " then end            next        print "c out = " ; len( bits1 ) , bits1        dim as string final = ""    for a as longint = 1 to len( bits1 ) step 2        final+= chr( val( "&H" + mid( bits1 , a , 2 ) ) )    next        print "c fin = " ; len(final)       return final   end function'==============================================================================='============================================================================Function decompress_loop( chrs as string ) as string        print    print "d inp = " ; len( chrs )    dim as string bits = ""    for a as longint = 1 to len( chrs ) step 1        bits+= right( "00" + hex( chrs[ a - 1 ] ) , 2 )    next        print "d bit = " ; len( bits ) , bits        return chrs   end function`
albert
Posts: 5927
Joined: Sep 28, 2006 2:41
Location: California, USA

### Re: Squares

@Dodicat

I found a flaw in my method....

if you have a 5 , 0 then the output would be 5 , 5
if you have a 5 , 10 then the output would be 5 , 5

So : i got to make it go by 6 bits , and add 1 to every number , so we can't have a 5 , 0
albert
Posts: 5927
Joined: Sep 28, 2006 2:41
Location: California, USA

### Re: Squares

@Dodicat

I converted it to 6 bits input... I got it returning correct , about 80% of the time....

==================================
v1 = val( "&B" + mid( n1 , 1 , 3 ) ) + 1
v2 = val( "&B" + mid( n1 , 4 , 3 ) ) + 1

if v1 < v2 then v3 = ( v2 - v1 )
if v1 > v2 then v3 = ( v2 )
if v1 = v2 then v3 = 0

bits1+= hex( v1 ) + hex( v3 )
==================================

Got to get "val1" to equal "v2"

Still compresses 100,000 bytes by 98% after 100 loops...Takes about 8 to 10 seconds

Code: Select all

`Declare Function      compress_loop( chrs as string ) as stringDeclare Function decompress_loop( chrs as string ) as stringscreen 19'====================================================================='====================================================================='start program'====================================================================='=====================================================================dim as double time1 , time2 , time3 , time4do       randomize       dim as string s = ""    For n As Long = 1 To 8        s+=chr(Int(Rnd*256))    Next       time1=timer    'begin compress        dim as string comp = s            'do            '    dim as longint chk = len(comp) - 1            '    comp = compress_loop(comp)            '    if len(comp) >= chk then exit do            '    if inkey = chr( 27 ) then end            'loop            for a as longint = 1 to 1 step 1                comp = compress_loop(comp)            next    'end compress    time2 = timer       time3=timer    'begin decompress        dim as string final_out = comp        for a as longint = 1 to 1 step 1            final_out = decompress_loop(final_out)        next    'end decompress    time4 = timer      'sleep       print string(99,"=")    print "inp = " ; (s)    print string(99,"=")    print "out = " ; (final_out)    print    print "compress time   = "; time2-time1    print "decompress time = "; time4-time3    print       if s = final_out then print "Decompressed OK" else print "Decompression failed."    print string(99,"=")       sleep   loop until inkey = chr(27)sleepend'==============================================================================='==============================================================================='compress'==============================================================================='===============================================================================Function compress_loop( chrs as string ) as string       print "c inp = " ; len(chrs) ' , chrs        dim as string bits = ""    dim as string n1    dim as ubyte ptr usp = cptr( ubyte ptr , strptr( chrs ) )    for a as longint = 1 to len( chrs ) step 1        n1 = "00000000" + bin( *usp ) : usp+= 1        n1 = right( n1 , 8 )        bits+= n1    next        print "c bin = " ; len( bits ) , bits        print "  n1" , "v1" , "v2" , "v3" , "answer"    dim as string bits1 = ""    dim as string n2    dim as longint v1 , v2 , v3    for a as longint = 1 to len( bits ) step 6                n1 = mid( bits , a , 6 )                v1 = val( "&B" + mid( n1 , 1 , 3 ) ) + 1        v2 = val( "&B" + mid( n1 , 4 , 3 ) ) + 1                if v1 < v2 then v3 = ( v2 - v1 )        if v1 > v2 then v3 = ( v2 )        if v1 = v2 then v3 = 0                bits1+= hex( v1 ) + hex( v3 )                dim as longint val1                if v1 > v3 then val1 = v3 else val1 = v3 + v1                if v3 = 0 then val1 = v1                print n1 , v1 , v2 , v3 , val1        sleep        if inkey = " " then end            next        print "c out = " ; len( bits1 ) , bits1        dim as string final = ""    for a as longint = 1 to len( bits1 ) step 2        final+= chr( val( "&H" + mid( bits1 , a , 2 ) ) )    next        print "c fin = " ; len(final)       return final   end function'==============================================================================='============================================================================Function decompress_loop( chrs as string ) as string        print    print "d inp = " ; len( chrs )    dim as string bits = ""    for a as longint = 1 to len( chrs ) step 1        bits+= right( "00" + hex( chrs[ a - 1 ] ) , 2 )    next        print "d bit = " ; len( bits ) , bits        return chrs   end function`
albert
Posts: 5927
Joined: Sep 28, 2006 2:41
Location: California, USA

### Yah-Zip ( Test Bed )

@Dodicat

Getting closer!!!
It's returning correct in all cases , except for when v2 = 8

How would you handle the case of v2 = 8 ???

Code: Select all

`Declare Function      compress_loop( chrs as string ) as stringDeclare Function decompress_loop( chrs as string ) as stringscreen 19'====================================================================='====================================================================='start program'====================================================================='=====================================================================dim as double time1 , time2 , time3 , time4do       randomize       dim as string s = ""    For n As Long = 1 To 8        s+=chr(Int(Rnd*256))    Next       time1=timer    'begin compress        dim as string comp = s            'do            '    dim as longint chk = len(comp) - 1            '    comp = compress_loop(comp)            '    if len(comp) >= chk then exit do            '    if inkey = chr( 27 ) then end            'loop            for a as longint = 1 to 1 step 1                comp = compress_loop(comp)            next    'end compress    time2 = timer       time3=timer    'begin decompress        dim as string final_out = comp        for a as longint = 1 to 1 step 1            final_out = decompress_loop(final_out)        next    'end decompress    time4 = timer      'sleep       print string(99,"=")    print "inp = " ; (s)    print string(99,"=")    print "out = " ; (final_out)    print    print "compress time   = "; time2-time1    print "decompress time = "; time4-time3    print       if s = final_out then print "Decompressed OK" else print "Decompression failed."    print string(99,"=")       sleep   loop until inkey = chr(27)sleepend'==============================================================================='==============================================================================='compress'==============================================================================='===============================================================================Function compress_loop( chrs as string ) as string       print "c inp = " ; len(chrs) ' , chrs        dim as string bits = ""    dim as string n1    dim as ubyte ptr usp = cptr( ubyte ptr , strptr( chrs ) )    for a as longint = 1 to len( chrs ) step 1        n1 = "00000000" + bin( *usp ) : usp+= 1        n1 = right( n1 , 8 )        bits+= n1    next        print "c bin = " ; len( bits ) , bits        print    print "  n1" , "v1" , "v2" , "v3" , "answer"    dim as string bits1 = ""    dim as string n2    dim as longint v1 , v2 , v3    for a as longint = 1 to len( bits ) step 6                n1 = mid( bits , a , 6 )                v1 = val( "&B" + mid( n1 , 1 , 3 ) ) + 1        v2 = val( "&B" + mid( n1 , 4 , 3 ) ) + 1                if v1 < v2 then v3 = v2 xor 8        if v1 > v2 then v3 = v2        if v1 = v2 then v3 = 0                 bits1+= hex( v1 ) + hex( v3 )                dim as longint val1 = v3 xor 8                if v1 > v3 then val1 = v3                if v3 = 0 then val1 = v1                if val1 <> v2 then n2 = "X" else n2= "="                print n1 , v1 , v2 , v3 , val1 , n2        sleep        if inkey = " " then end            next        print "c out = " ; len( bits1 ) , bits1        dim as string final = ""    for a as longint = 1 to len( bits1 ) step 2        final+= chr( val( "&H" + mid( bits1 , a , 2 ) ) )    next        print "c fin = " ; len(final)       return final   end function'==============================================================================='============================================================================Function decompress_loop( chrs as string ) as string        print    print "d inp = " ; len( chrs )    dim as string bits = ""    for a as longint = 1 to len( chrs ) step 1        bits+= right( "00" + hex( chrs[ a - 1 ] ) , 2 )    next        print "d bit = " ; len( bits ) , bits        return chrs   end function`

Here's your Zlib doing the compression... Compresses 87% after 100 loops... Takes ~16 seconds

Code: Select all

`Declare Function   compress_loop( chrs as string ) as stringDeclare Function decompress_loop( chrs as string ) as stringNamespace Zlibrary#inclib "zlib"Extern "C"    Declare Function compressBound(Byval sourceLen As Ulong) As Ulong    Declare Function uncompress(Byval dest As Ubyte Ptr, Byval destLen As Uinteger Ptr, Byval source As  Ubyte Ptr, Byval sourceLen As Ulong) As Long    Declare Function compress(Byval dest As Ubyte Ptr, Byval destLen As Uinteger Ptr, Byval source As  Ubyte Ptr, Byval sourceLen As Ulong) As LongEnd ExternFunction getpassedinfo(text As String,Byref passed_length As Integer) As String    Dim As String var1,var2    Dim As Integer pst    #macro splice(stri,char,var1,var2)    pst=Instr(stri,char)    var1="":var2=""    If pst<>0 Then        var1=Mid(stri,1,pst-1)        var2=Mid(stri,pst+1)    Else        var1=stri    End If    #endmacro    splice(text,"|",var1,var2)    text=var2    passed_length=Valint(var1)    Return textEnd Function'=================   UNPACK ===============Function unpack(file As String) As String    Dim As Integer passed_length    Dim As String text=getpassedinfo(file,passed_length)    Dim As Integer stringlength,destinationlength    stringlength=Len(text)    destinationlength =passed_length    Dim As Ubyte Ptr source    Dim As Ubyte Ptr  destination =Callocate(destinationlength,1)    source=@text[0]    Var mistake=uncompress(destination,@destinationlength, source, stringlength)    If mistake<>0 Then Print "There was an error":Sleep:End    Dim As String uncompressed    uncompressed=String(destinationlength,0)    For i As Integer = 0 To destinationlength- 1        uncompressed[i]=(destination[i])    Next    Deallocate destination    Return uncompressedEnd Function'===================  PACK ============Function pack(file As String) As String    Dim As String text=file    Dim As Integer stringlength,destinationlength    stringlength=Len(text)    destinationlength = compressBound(stringlength)    Dim As Ubyte Ptr source    Dim As Ubyte Ptr destination =Callocate(destinationlength,1)    source=@text[0]    Var mistake=compress(destination, @destinationlength, source, stringlength)    If mistake <>0 Then Print "There was an error"    Dim As String compressed    compressed=String(destinationlength,0)    For n As Integer=0 To destinationlength-1        compressed[n]=destination[n]    Next n    compressed=stringlength &"|"+compressed    Deallocate destination    Return compressedEnd FunctionEnd Namespace'=================================================================='=================================================================='test zipper'=================================================================='==================================================================screen 19Dim Shared As String sRandomizes=""dim as string check=""dim as string compare=""dim as longint length = 0dim as double compression = 0dim as longint loops = 0dim as double time1 , time2time1 = timerdo       loops+=1       'one time run , create initial string    if loops = 1 then        For n As Long = 1 To 100000            s+=chr(Int(Rnd*256))'+48        Next        compare =  s        length = len(s)    else        'modify compression to make further compression possible               s = compress_loop(s)        end if    check = s    compression = (100 - ( 100 / ( length / len(check) ) ))       Print "original string"    Print Len(s)    Print       Dim As String compressed=Zlibrary.pack(s)    s = compressed       Print "packed string "    Print Len(compressed)    Print       Dim As String uncompressed=Zlibrary.unpack(compressed)       Print "Retrieve"    Print Len(uncompressed)    Print    'Print "compression ratio  "; 100 - ( 100 / ( Len(s) / len(compressed) ) ) ; "%"    Print "compression ratio  "; 100 - ( 100 / ( length / len(s) ) ) ; "%"    Print Iif(uncompressed=check,"OK","ERROR")    Print "-------------------------------"       'sleep 1000       'if loops > 2 and (100 - ( 100 / ( length / len(s) ) )) < compression then exit do       print "press esc to exit."    print    print "press a key for next compression." ; " loops = " ; loops ; " out of 100."    'sleep        if inkey = chr(27) then exit do   loop until loops = 100time2 = timerprintprint  "Compress time = " ; time2 - time1printprint "Press a key to decompress."sleeps = str(loops) + "_" + s ' save as an output file...'=================================================================='decompress'==================================================================dim as longint dec = instr(1,s,"_")dim as longint count = val(left(s,dec-1))dim as string comp = mid(s,dec+1)dim as string val1dim as string outsfor a as longint = count to 2 step -1    s = Zlibrary.unpack(comp)    outs = decompress_loop(s)    comp = outsnextcomp = Zlibrary.unpack(comp)printprint "input = "; length , "output = " ; len(comp) , "compression ratio  "; 100 - ( 100 / ( length / len(s) ) ) ; "%"printif comp = compare then print "Decompression successful." else print "ERROR"printprintPrint "!!~~Done~~!!"Sleepend'==============================================================================='============================,==================================================='begin functions'==============================================================================='================='==============================================================Function compress_loop( chrs as string ) as string       print "c inp = " ; len(chrs) ' , chrs        dim as string bits = ""    dim as string n1    dim as ubyte ptr usp = cptr( ubyte ptr , strptr( chrs ) )    for a as longint = 1 to len( chrs ) step 1        n1 = "00000000" + bin( *usp ) : usp+= 1        n1 = right( n1 , 8 )        bits+= n1    next        print "c bin = " ; len( bits ) ', bits        dim as string bits1 = ""    dim as longint v1 , v2 , v3    for a as longint = 1 to len( bits ) step 6                n1 = mid( bits , a , 6 )                v1 = val( "&B" + mid( n1 , 1 , 3 ) ) + 1        v2 = val( "&B" + mid( n1 , 4 , 3 ) ) + 1                if v1 < v2 then v3 = v2 xor 8        if v1 > v2 then v3 = v2        if v1 = v2 then v3 = 0                bits1+= hex( v1 ) + hex( v3 )            next        print "c out = " ; len( bits1 ) ' , bits1        dim as string final = ""    for a as longint = 1 to len( bits1 ) step 2        final+= chr( val( "&H" + mid( bits1 , a , 2 ) ) )    next        print "c fin = " ; len(final)       return final   end function'==============================================================================='============================================================================Function decompress_loop( chrs as string ) as string        print    print "d inp = " ; len( chrs )    return chrs   end function`
albert
Posts: 5927
Joined: Sep 28, 2006 2:41
Location: California, USA

### Re: Squares

@Dodicat

Never mind!!
It can't be resolved.. All you have is v1 and 0..

You can't tell if 0 is supposed to equal v1 or 8... you have to guess...and guessing between 2 values can't be resolved...

I got to figure out how the Space Aliens , compress data....
Posts: 2184
Joined: May 24, 2007 22:10
Location: The Netherlands

### Re: Squares

albert wrote:I got to figure out how the Space Aliens , compress data....

Why, maybe they have unlimited storage. Maybe to have invented time-travel, so they can just delete data and go back in time to retrieve it. The ultimate Wayback Machine.
dodicat
Posts: 6767
Joined: Jan 10, 2006 20:30
Location: Scotland

### Re: Squares

Data is a human concept.
For instance navigators use an ephemeris, the projected trajectories (positions of celestial bodies) including now satellites.
Also tables of tides, currents.
Each year new data is published, in book form or digital form of one kind or another.
We need the travel data because we are not designed for travel.
But the albatross, a much superior traveller than us, seems to need nothing.
Recently (a few hundred years) we started keeping records, hard copies on paper or vellum i.e. data
Now that era has finished and our records (data) is now stored on a magnetic or silicon medium, which has a very short lifespan.
So the moment we cease updating our data it will be all lost within a short time (50 years?), whether compressed or not.
So what form are these space aliens, more human like than albatross like?
I would really like to think they are more of of the bird brain variety.
Richard
Posts: 3047
Joined: Jan 15, 2007 20:44
Location: Australia

### Re: Squares

Albert wrote:I got to figure out how the Space Aliens , compress data....
That is an easy question. They store information on the event horizon surface of Black Holes as a hologram. As the information crosses the event horizon, it's passage is recorded in the event horizon surface by the strings that form the information. The surface has zero thickness, so one physical dimension is removed. In effect, as it has the dimension removed, the volume of information is compressed infinitely, to an area with zero volume. Everything consumed by a black hole is recorded in it's event horizon by the strings connected to the compressed information.
albert
Posts: 5927
Joined: Sep 28, 2006 2:41
Location: California, USA

### Re: Squares

@Dodicat

Check this one out!!!

Compresses 100,000 bytes in 98% , after 30 loops..

Code: Select all

`Declare Function      compress_loop( chrs as string ) as stringDeclare Function decompress_loop( chrs as string ) as stringscreen 19'====================================================================='====================================================================='start program'====================================================================='=====================================================================dim as double time1 , time2 , time3 , time4do       randomize       dim as string s = ""    For n As Long = 1 To 8        s+=chr(Int(Rnd*256))    Next       time1=timer    'begin compress        dim as string comp = s            'do            '    dim as longint chk = len(comp) - 1            '    comp = compress_loop(comp)            '    if len(comp) >= chk then exit do            '    if inkey = chr( 27 ) then end            'loop            for a as longint = 1 to 1 step 1                comp = compress_loop(comp)            next    'end compress    time2 = timer       time3=timer    'begin decompress        dim as string final_out = comp        for a as longint = 1 to 1 step 1            final_out = decompress_loop(final_out)        next    'end decompress    time4 = timer      'sleep       print string(99,"=")    print "inp = " ; (s)    print string(99,"=")    print "out = " ; (final_out)    print    print "compress time   = "; time2-time1    print "decompress time = "; time4-time3    print       if s = final_out then print "Decompressed OK" else print "Decompression failed."    print string(99,"=")       sleep   loop until inkey = chr(27)sleepend'==============================================================================='==============================================================================='compress'==============================================================================='===============================================================================Function compress_loop( chrs as string ) as string       print "c inp = " ; len(chrs) ' , chrs        dim as string bits = ""    dim as string n1    dim as ubyte ptr usp = cptr( ubyte ptr , strptr( chrs ) )    for a as longint = 1 to len( chrs ) step 1        n1 = "00000000" + bin( *usp ) : usp+= 1        n1 = right( n1 , 8 )        bits+= n1    next        print "c bin = " ; len( bits ) , bits        dim as string bits1 = ""    dim as string bits2 = ""    for a as longint = 1 to len( bits ) step 2                n1 = mid( bits , a , 2 )                if n1 = "00" then bits1+= "0" : bits2+= "1"        if n1 = "01" then bits1+= "1" : bits2+= "1"        if n1 = "10" then bits2+= "0"        if n1 = "11" then bits2+= "10"            next        print "c out = " ; len( bits1 ) , bits1    print "c out = " ; len( bits2 ) , bits2        dim as string final = ""    for a as longint = 1 to len( bits1 ) step 8        final+= chr( val( "&B" + mid( bits1 , a , 8 ) ) )    next    final+= "END"    for a as longint = 1 to len( bits2 ) step 8        final+= chr( val( "&B" + mid( bits2 , a , 8 ) ) )    next        print "c fin = " ; len(final)       return final   end function'==============================================================================='============================================================================Function decompress_loop( chrs as string ) as string        print    print "d inp = " ; len( chrs )    return chrs   end function`
albert
Posts: 5927
Joined: Sep 28, 2006 2:41
Location: California, USA

### Re: Squares

@Richard

The Alien Orbs , at the center , was a small 2 inch diameter sphere..
The sphere was like a Rubik's cube.
The section bands , were rotating around horizontally and vertically as it was talking...
They could speak in any Alien or Earth language..

Plus they had multi-colored lasers and could light up in any color...And output lasers in any color...
They were making rainbow circles on the ground..
And when i walked through , one of the rainbow circles , i turned and looked down and my footprints were glowing in a turquoise color..
They were heat-mapping my footprints and lasering them out in a color....

To do all they could do , would require data compression , to hold all that info in a small 2 inch sphere.... plus the batteries , motors and lasers...

?????