swap syntax error

[Hard]

hi there

just a little question. is this how it was supposed to be:

Code: Select all

swap bla, blub  'works
swap(bla, blub) 'doesnt

thanks - hard

[Zippy]

hi there

just a little question. is this how it was supposed to be:

Code: Select all

swap bla, blub  'works
swap(bla, blub) 'doesnt

thanks - hard

Yes.

[nobozoz]

Hard,

As far as I can tell, 'Swap' is a direct pointer swap without any syntax checking by the compiler.

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Dim bla as integer = 7
Dim blub as double = 5.0

Print @bla,@blub,bla,blub
Swap bla, blub
Print @bla,@blub,bla,blub
'... etc

Don't know why you'd do this intentionally, but the results can be "interesting".

Jim

[cha0s]

Could you print the output of your program, nobozoz? I'm still working on getting fbc to work here...

[Hard]

[cha0s]

Oh crazy. Is this the same result you'd get as if you did:

Code: Select all

Dim blub As Double = 5.0
blub = *cast(integer ptr, @blub)
print blub

?

[Hard]

unnessesary to make a screeny here, but i didnt want to be a combo breaker :D

btw:

Code: Select all

DIM blub As DOUBLE = 5
blub = *cast(Integer Ptr, @blub)
Print blub '0

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DIM blub As INTEGER = 5
blub = *cast(Integer Ptr, @blub)
Print blub '5

[jevans4949]

btw: ...

Not surprising, since the business part of a double containing 5 is stored in memory at the highest address, and the lowest bits contain zeros.

Code: Select all

Union xx
d As Double
b(0 To 7) As UByte 
End Union

Dim blub As xx

blub.d = 5

For i As Integer = 0 To 7
    Print Hex(blub.b(i),2);
Next
Print
Sleep

EDIT: prints 0000000000001440