Search found 5944 matches

by albert
Dec 28, 2009 4:39
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

I just posted at the same time as you its above your last post!

I changes the deg variable to 1 and all the numbers stayed the same so i finally figured out the y's were cancelling each other out , so i deleted the post.
by albert
Dec 28, 2009 4:33
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

@Albert. A right triangle with sides x, y and hypotenuse r obeys Pythagoras' r^2 = x^2 + y^2 We get: r = Sqr(x^2 + y^2) x = Sqr(r^2 – y^2) y = Sqr(r^2 – x^2) From the side lengths we can use trigonometry to define or find Sin(a) = y / r Cos(a) = x / r Tan(a) = y / x and it follows that : x = r * Co...
by albert
Dec 27, 2009 23:06
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

Richard I think i got it now: Degrees from sine dim as double rad = atn(1)/45 dim as double x,y,deg for deg = 0 to 90 step 1 y=sin(deg*rad) 'trying to get degrees from sine print deg, ( 1/ ( y / (y*deg*rad) ) ) /rad , ' trying to mimic the formula 'print ( 1 / (rad/deg/rad/rad) ) / rad 'same result ...
by albert
Dec 27, 2009 22:15
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

I'm trying to get the degrees from the sine, to rework pythagoras therom to get the tan, kinda rotating the equations around to solve for tan(). dim as double rad = atn(1)/45 dim as double x,y,deg for deg = 0 to 90 step 1 y=sin(deg*rad) 'trying to get degrees from sine print deg, ( deg / ( y / (y*ra...
by albert
Dec 27, 2009 19:43
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

tangent / sqr(1+tan*tan) = sine

basically tan / C = sine

So if we make up a Tan number, we can derive the sine for that number.

Richard is there a way to work the formula to get even degrees from it
Maybe some super symetry or something?
by albert
Dec 27, 2009 5:22
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

I found a way to derive the sine and cosine from the tangent for what its worth??????? dim as double rad=atn(1)/45 dim as double x,y,deg print " deg sine cosine" for deg = 0 to 90 step 1 y=tan(deg*rad) x=sqr( 1 + y*y) print deg , (y/x) , (y/x/y) next deg sleep
by albert
Dec 26, 2009 21:20
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

dodicat i'll check out your calc today sometime the above code is pretty interesting. (I cut and pasted it and ran it.) Could you post a link to it? @Richard or others The atan2( y , x ) * 90 / pion2 can that be reworked to give the tangent such as: 90 / pion2 * ??? = degree I was wondering, since t...
by albert
Dec 26, 2009 3:52
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

The calculator uses number1 and number2 internally for all 2 number functions and number1 for the square root function number1 is the top input window number2 is the bottom input window I haven't looked at the code in months so i can't remember but i think outtext is the preoutput in all functions i...
by albert
Dec 26, 2009 2:15
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

How about you guy's helping to create a workable formula. If I use the power series in my calculator at an estimated 300 iterations to get 1,000 place accuracy, it will take about 1 minute times 300 to get a single sine, thats about 5 hours; plus the factoring,dividing and addition will add a few mo...
by albert
Dec 25, 2009 23:46
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

If you open a pair of scissors to a 90 degree angle, thats 0 degrees if you close them in increments of the chord of one degree you have the sine function. The tangent of the chord goes from near vertical at 1 to near horizontal at 90 in even increments. the height of the tangent throughout its incr...
by albert
Dec 25, 2009 21:04
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

The sine and cosine both squared and added together equals 1 in all cases. (sin*sin + cos*cos) = 1 at 45 degrees its split .5 and .5 The chord remains the same in all degrees .0174530709 somehow there is a way to get the sin and cos from 1. With all the math knowledge you guys have one of you should...
by albert
Dec 24, 2009 3:59
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

Frosty the hooker had a twat packed full of snow and she'd blow your pipes if the price was right and set your nose aglow. Frosty the hooker was a fairy tale they say without the snow but the guys all know how they'd stand inline to pay. ------------------------------------------------- Now there mu...
by albert
Dec 24, 2009 0:15
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

I apperciate your effort Richard but I can't put it into my calculator the line is off from the cosine line more than my tangent formula is off from the tangent function line. My "Pro-Draw" i did in 1995-1999 had two different sections: 1. you could move the dot accros the screen at an ang...
by albert
Dec 23, 2009 3:18
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

One of the other posters already explained and showed the 1/cos(deg) thingy. What i was getting to; was the ratios of sine and cosine from the c^2 for example take 60 degrees. (90/60) = 1.5 reduces to .75 (30/60) = .5 reduces to .25 extract the square roots and you have the sine of both 30 and 60. T...
by albert
Dec 22, 2009 21:50
Forum: General
Topic: Circles
Replies: 1988
Views: 220108

"C" = sqr( (1*1) + ( tan*tan) ) or "C" = tan(deg) * tan(deg/2) + 1 Somehow there should be a way of determining which portions of c^2 = the sin and what portion equals the cosine. ============================================== I noticed that the "C" value of 45 degrees ...